Java – deliberately cause Deadlock
Tuesday, August 4th, 2015
Another interview question.
When this code is executed runnable1 will wait for a lock on “b” and runnable2 will wait for a lock on “a”.
package test;
/**
* Deliberately try and cause deadlock
*
*/
public class DeadLockTest {
public static void main(String[] args) {
final Object a = new Object();
final Object b = new Object();
final Runnable runnable1 = new Runnable() {
public void run() {
synchronized (a) {
try {
Thread.sleep(100); // Adding delay to increase chance of deadlock
} catch (InterruptedException e) {
e.printStackTrace();
}
synchronized (b) { // We already have "a" abut need "b" too
System.out.println("In runnable1");
}
}
}
};
final Runnable runnable2 = new Runnable() {
public void run() {
synchronized (b) { // Has "b" but needs "a"
synchronized (a) {
System.out.println("In runnable2");
}
}
}
};
new Thread(runnable1).start();
new Thread(runnable2).start();
}
}
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Tags: java
Posted in: Interview Questions